36x^2+72x+11=0

Solution for 36x^2+72x+11=0 equation:

36x^2+72x+11=0

a = 36; b = 72; c = +11;
Δ = b2-4ac
Δ = 722-4·36·11
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-60}{2*36}=\frac{-132}{72}
=-1+5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+60}{2*36}=\frac{-12}{72}
=-1/6
$